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The amount of urea to be dissolved in 500 ml of water (K =18.6 K mole-1 in 100g solvent) to produce a depression of 0.1860C in freezing point is

  • Option 1)

    9 g

  • Option 2)

    6 g

  • Option 3)

    3 g

  • Option 4)

    0.3 g

 

Answers (1)

best_answer

As we learned

 

Mathematical Expression of Depression in Freezing point -

\Delta T_{f}= K_{f}\: m
 

- wherein

m = molarity of solvent 

K_{f} = cryoscopic  constant

    molal depress const

Units = \frac{K-K_{g}}{mole}

 

 

\Delta T_{f}=\frac{100\times K\times w}{m\times W}\; \; \therefore 0.186=\frac{100\times 1.86\times w}{60\times 500};\: \: w=3g

 

 


Option 1)

9 g

Option 2)

6 g

Option 3)

3 g

Option 4)

0.3 g

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Plabita

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