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  • Confused! kindly explain, Three charges of (+2q), (– q) and (– q) are placed at the corners A, B and C of an equilateral triangle of side a as shown in the adjoining figure. Then the dipole moment of this combination is

Three charges of (+2q), (– q) and (– q) are placed at the corners A, B and C of an equilateral triangle of side a as shown in the adjoining figure. Then the dipole moment of this combination is

  • Option 1)

    qa

  • Option 2)

    zero

  • Option 3)

    qa\sqrt3

  • Option 4)

    \frac{2}{\sqrt3}qa

 

Answers (1)

best_answer

As we have learned

Dipole moment -

\left ( \vec{P} \right )=q\left ( \vec{2l} \right )

S.I unit - C-m or Debye

1\, Debye=3.3\times 10^{-30}c-m

 

 

- wherein

2l\rightarrow dipole\, length

 

 

 

 

The charge +2q can be broken in +q, +q. Now as shown in figure we have two equal dipoles inclined at an angle of 60o. Therefore resultant dipole moment will be

P_{net}= \sqrt{p^2+P^2+2PP \cos 60}

=\sqrt3 p= \sqrt3 qa 

 


Option 1)

qa

Option 2)

zero

Option 3)

qa\sqrt3

Option 4)

\frac{2}{\sqrt3}qa

Posted by

Plabita

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