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Consider the figure and mark the correct option

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Option: 1

Activation energy of forward reaction is E_{1}+E_{2}  and product is less stable than reactant. 


Option: 2

Activation energy of forward reaction is E_{1}+E_{2}  and product is more stable than reactant. 


Option: 3

Activation energy of both forward and backward reaction is E_{1}+E_{2}  


Option: 4

Activation of backward reaction is E_2 and forward reaction is E_1


Answers (1)

best_answer

The given figure  is -

From above graph,

\mathrm{\textup{Activation energy of forward reaction } = E_1+E_2}

\mathrm{\textup{Activation energy of backward reaction } = E_1}

Here, Product energy is more than reactant energy. So, the reactant is more stable than the product.

Therefore, option(1) is correct

 

 

 

Posted by

chirag

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