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Dimentional Formula of Gravitational Potential is 

Option: 1

\left [ {ML^{2}T^{-1}} \right ]


Option: 2

\left [ {M^{0}L^{2}T^{-3}} \right ]


Option: 3

\left [ {ML^{2}T^{-2}} \right ]


Option: 4

\left[M^{0} L^{2} T^{-2}\right]


Answers (1)

best_answer

As we learn

Gravitational Potential -

Scalar Quantity defined as workdone per unit mass

Unit \to \; Joule/kg \; or \; m^{2}/sec^{2}

Dimension\: :\; \left [ M^{0}L^{2}T^{-2} \right ]

- wherein

V=-\frac{W}{m}=-\int \frac{\overrightarrow{F}\cdot \overrightarrow{dr}}{m}

V=-\int \overrightarrow{I}\cdot \overrightarrow{dr}

V\rightarrow Gravitational potential

I\rightarrow Field Intensity

dr\rightarrow small distance

 

  As 

V=\frac{-GM}{r}

\left [ V \right ]=\frac{\left [ G \right ]\left [ M \right ]}{\left [ r \right ]}=\frac{\left [ M^{-1}L^{3}T^{-2} \right ].\left [ M \right ]}{\left [ L \right ]}=\left [ M^{0}L^{2}T^{-2} \right ]

 

 

Posted by

vinayak

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