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Dispersive power for crown glass if\mu _{v}=1.523 ,\mu _{r}=1.5145 is:

Option: 1

0.1639


Option: 2

0.1821


Option: 3

0.1764


Option: 4

0.2123


Answers (1)

best_answer

As we learn

Dispersive power (ω) -

\omega = \frac{\mu _{v}-\mu _{r}}{\mu _{y}-1}

- wherein

\mu _{v} = Refractive index of violet

\mu _{r}= Refractive index of red

\mu _{y}= Refractive index of yellow

= \frac{\mu_{v}+\mu_{r}}{2}

 

 w= \frac{\mu_{v}-\mu_{r}}{\mu _{y}-1}

\mu _{y}= \frac{\mu_{v}+\mu_{r}}{2}=1.5187

\therefore w=\frac{1.523-1.5145}{1.5187-1}=0.1639

 

Posted by

Shailly goel

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