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During chlorination of methane to methyl chloride, the propagation step is represented by:

Option: 1

Cl - Cl \overset{hv}{\rightarrow} Cl + Cl


Option: 2

\dot{CH_{3}}+\dot{Cl}\rightarrow CH_{3}Cl


Option: 3

\dot{CH_{3}}+{Cl-Cl}\rightarrow {CH_{3}-Cl}+\dot{Cl}


Option: 4

\dot{Cl}+\dot{Cl}\rightarrow Cl - Cl


Answers (1)

 

Preparation of haloalkane by free radical halogenation of Alkanes -

Alkanes undergo free radical substitution reaction when treated Cl2/Br2 in presence of sunlight.

- wherein

CH_{4}+Cl_{2}\rightarrow CH_{3}Cl+HCl

 

 

 

Hence, option (3) is correct.

Posted by

Ramraj Saini

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