Get Answers to all your Questions

header-bg qa

During the propagation of electromagnetic waves in a medium :  

Option: 1

Electric energy density is double of the magnetic energy density.      
 


Option: 2

Electric energy density is half of the magnetic energy density.     
 


Option: 3

Electric energy density is equal to the magnetic energy density.       
 


Option: 4

Both electric and magnetic energy densities are zero.      


Answers (1)

best_answer

As we have learned in

Speed of light formula in vacuum -

c=\frac{1}{\sqrt{\mu_{o}\epsilon _{o}}}

c=2.99793 X 10^{8} m/s

- wherein

c = Speed of light in vacuum

\mu_{o} = Permeability of vacuum

\epsilon _{o} = Permittivity of vacuum

 

 E_{0}= CB_{0}   and   c=\frac{1}{\sqrt{\mu_{o}\epsilon _{o}}}

Electric Energy density = \frac{1}{2}\epsilon _{0}{E_{0}}^{2}= \mu _{E}

Magnetic Energy density = \frac{1}{2}\frac{{B_{0}}^{2}}{{\mu _{1}}^{2}}= \mu _{B}

Thus, \mu _{E}= \mu _{B}

Energy is equally divided between electric and magnetic fields.

 

Posted by

Suraj Bhandari

View full answer