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  • Five boys and three girls are seated at random in a row. The probability that no boy sits between two girls is  Option: 1 <img alt="\f

Five boys and three girls are seated at random in a row. The probability that no boy sits between two girls is

 

Option: 1

\frac{1}{56}


Option: 2

\frac{1}{8}


Option: 3

\frac{3}{28}


Option: 4

None of these


Answers (1)

best_answer

\mathrm{n(S)=8 !}

\mathrm{n(E)=} The number of arrangements of 5 boys and 3 girls when the 3 girls are consecutive \mathrm{=6 ! \times 3 !}

\therefore  The required probability =\frac{6 ! \times 3 !}{8 !}=\frac{3}{28}

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Anam Khan

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