Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:(NEET 2018)

  1. 60 ml \frac{M}{10} HCl + 40 ml \frac{M}{10} NaoH
  2. 55 ml \frac{M}{10} HCl + 45 ml \frac{M}{10} NaOH
  3. 75 ml\frac{M}{5} HCl + 25 ml \frac{M}{5}NaOH
  4. 100 ml \frac{M}{10} HCl + 100 ml \frac{M}{10} NaOH

pH of which one of them will be equal to 1 ?

Answers (1)

The p(H) scale -

Hydronium ion concentration in molarity is more conveniently expressed on a logarithmic scale known as p(H) scale.

- wherein

The p(H) of a solution is defined as negative logarithm to base 10 of the activity of hydrogen ion

P(H)=-log[H^{+}]

 

 As N1V1 > N2V2 so acid left at the end of the reaction

N_{mixture} = [H]^{+} =\frac{N_{1}V_{1} - N_{2}V_{2}}{V_{1} + V_{2}} = \frac{\frac{1}{5}X75 - \frac{1}{5}X25 }{75+25} = \frac{1}{10} = 10^{-1}

pH = -log10^{-1} = 1

 

So acid is left at the end of the reaction

Option 4)

c

This is correct.

Posted by

Ankit

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: IIT Roorkee’s ECE emerges as top choice after CSE; closing rank rises
anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus

Latest Question