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For a chemical reaction, A \rightarrow products, the rate of reaction doubles when the concentration of A is increased by 4 times. The order of reaction is:

Option: 1

4


Option: 2

1/2


Option: 3

2


Option: 4

1


Answers (1)

best_answer

For a chemical reaction, A \rightarrow products,

\mathrm{r}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}} \ldots \ldots(\mathrm{i})

The rate of reaction doubles when the concentration of A is increased by 4 times.

So,

2 \mathrm{r}=\mathrm{k}[4 \mathrm{A}]^{n} \ldots \ldots . \text { (ii) }

Dividing (ii) by (i),

\\ \frac{2 \mathrm{r}}{\mathrm{r}}=\frac{\mathrm{k}}{\mathrm{k}}\left[\frac{4 \mathrm{A}}{\mathrm{A}}\right]^{\mathrm{n}} \\\\ 2=2^{2 \mathrm{n}} \\\\ 2 \mathrm{n}=1 \text { or } \mathrm{n}=1 / 2

Therefore, option(2) is correct

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vinayak

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