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  • For a complex reaction, CH3COOH  CH4 + CO. experimental rate

For a complex reaction, CH3COOH \rightarrow CH4 + CO.
experimental rate law, r = k [CH3CHO]3/2, the order and molecularity respectively?

Option: 1

3/2 , 3/2


Option: 2

Not defined , 3/2


Option: 3

3/2 , Not defined


Option: 4

none of above


Answers (1)

best_answer

Order of the reaction is the sum of the power of concentration of reactant.

So, Order = 3/2
Molecularity is not defined for Complex (multi-step) reactions.

Therefore, option(3) is correct

Posted by

Devendra Khairwa

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