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For a measurement of diameter of a hollow cylinder following  calculation are obtained for absolute error of different measurment 

\Delta l_1 = 0.0 1\: \: \Delta l_2 = -0.02 \: \: \Delta l_3 = 0.06 \ \Delta l_4 = -0.01\: \: \Delta l_5 = 0.01

What will be the mean absolute error for the measurement ?

 

Option: 1

0.01


Option: 2

0.022


Option: 3

-0.01


Option: 4

-0.02


Answers (1)

best_answer

Mean absolute error -

= (0.01 + 0.02 + 0.06 + 0.01 + 0.01)/ 5

= 0.11/5=0.022

 

Posted by

Shailly goel

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