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For measurement of a length of the cylinder by vernier callipers following readings are taken 

3.29 cm     3.28 cm    3.29 cm     3.31 cm    3.28 cm    3.27 cm      3..29cm  3.30cm 

 Absolute error in measurement for 5th reading is  -  

Option: 1

-0.01


Option: 2

0.01


Option: 3

0.03


Option: 4

0.015


Answers (1)

best_answer

 mean value \bar l_m = \frac{3.29 + 3.28+3.29+3.31+3.28+3.27+3.29+3.30}{8}

\bar l_m =3.28875 \approx 3.29cm

\Delta a_{1}=\dpi{100} a_{m}- a_{1}

\Delta l_1 = 3.29-3.29 = 0.00 cm\\\\ \Delta l_2 = 3.29-3.28 = 0.01 cm\\\\ \Delta l_3 = 0.00 cm\\\\ \Delta l_4 = -0.02 cm\\\\ \Delta l_5 = 0.01 cm\\\\ \Delta l_6 = 0.02 cm\\\\ \Delta l_7 = 0.00 cm\\\\ \Delta l_8 = -0.01 cm\\\\

 Absolute error in measurement for 5th reading is= \Delta l_5 = +0.01 cm

 

 

Posted by

Gautam harsolia

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