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  • For two masses  following measurment are taken  <img alt="m_1 =

For two masses m_1 \: \: and \: \: m_2 following measurment are taken 

m_1 = (28.7 \pm 0.5) Kg \\\\ m_2 = (19.6\pm 0.3)Kg

What is the percentage error in M = m_1 + m_2

Option: 1

3.8 % 


Option: 2

1.6 % 


Option: 3

2.5 % 


Option: 4

3.5 % 


Answers (1)

best_answer

As we have learned

Percentage error in the value of x -

x= \frac{\left ( \Delta a+\Delta b \right )}{a+b}\times 100%

- wherein

\Delta a= absolute error in measurement of a

\Delta b= absolute error in measurement of b

\Delta x= absolute error in measurement of x

 

 \Delta m = \pm (\Delta m_1 + \Delta m_3) \\\\ \Delta m = \pm (0.5+0.3)\\\\ \Delta m = \pm 0.8 Kg

% error in M= \frac{\Delta m_1 + \Delta m_2 }{m_1 + m_2 } \times 100 \% \\\\ \frac{0.8}{48.3 } \times 100 \%= 1.6 \%

 

 

 

 

 

Posted by

chirag

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