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The molal elevation constant of water = 0.520C .The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl ), therefore, should be

  • Option 1)

    100.52^{\circ}C

     

     

     

  • Option 2)

    101.04^{\circ}C

  • Option 3)

    99.48^{\circ}C

  • Option 4)

    98.96^{\circ}C

 

Answers (1)

best_answer

As we learned 

 

Mathematical Expression -

\Delta T_{b}= K_{b}\: m

Unis of K_{b}=\frac{K-K_{g}}{mole}

\Delta T_{b}= Elevation\: in \: boiling\: point
 

- wherein

K_{b}= Boiling \: point \: elevation \: constant

m= molality

 

 \Delta T_{b}=imk_{b}=0.52\times 1\times 2=1.04

\therefore T_{b}=100+1.04=101.04^{\circ}C

 


Option 1)

100.52^{\circ}C

 

 

 

Option 2)

101.04^{\circ}C

Option 3)

99.48^{\circ}C

Option 4)

98.96^{\circ}C

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Plabita

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