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The potentials of the two plates of capacitor are +10V and –10 V. The charge on one of the plates is 40 C. The capacitance of the capacitor is 

  • Option 1)

    2F

  • Option 2)

    4F

  • Option 3)

    0.5F

  • Option 4)

    0.25F

 

Answers (1)

As we have learned

Common Potential -

V=\frac{Total\: charge}{Total\: capacity}=\frac{Q_{1}+Q_{2}}{C_{1}+C_{2}}

V=\frac{C_{1}V_{1}+C_{2}V_{2}}{C_{1}+C_{2}}

-

 

  

The potential difference across the parallel plate capacitor is 10V-(-10V)=20 V

Capacitance = Q/V=40/20=2F

 


Option 1)

2F

Option 2)

4F

Option 3)

0.5F

Option 4)

0.25F

Posted by

Vakul

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