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What is the probability of getting 9 Heads if Total coin toss = 11 ?

  • Option 1)

    110\times \left ( \frac{1}{2} \right )^{11}

     

     

     

  • Option 2)

    55\times \left ( \frac{1}{2} \right )^{10}

  • Option 3)

    55\times \left ( \frac{1}{2} \right )^{9}

  • Option 4)

    110\times \left ( \frac{1}{2} \right )^{12}

 

Answers (1)

best_answer

As we learned 

 

Probability of occurrence of an event -

Let S be the sample space then the probability of occurrence of an event E is denoted by P(E) and it is defined as 

P\left ( E \right )=\frac{n\left ( E \right )}{n\left ( S \right )}

P\left ( E \right )\leq 1

P(E)=\lim_{n\rightarrow\infty}\left(\frac{r}{n} \right )

 

 

- wherein

Where n repeated experiment and E occurs r times.

 

 

 

So P(H)=\frac{1}{2}=P(T)

P(9\: Heads)=_{}^{11}\textrm{C}_{9} \left ( \frac{1}{2} \right )^{11} =55\times \left ( \frac{1}{2} \right )^{11}=110\times \left ( \frac{1}{2} \right )^{12}


Option 1)

110\times \left ( \frac{1}{2} \right )^{11}

 

 

 

Option 2)

55\times \left ( \frac{1}{2} \right )^{10}

Option 3)

55\times \left ( \frac{1}{2} \right )^{9}

Option 4)

110\times \left ( \frac{1}{2} \right )^{12}

Posted by

Himanshu

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