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Given 

(a) n=5, m_{l}=+1

(b) n=2,l=1,m_{l}=-1,m_{s}=-\frac{1}{2}

Then maximum number of electron(s) in an atom that can have quantum numbers as given in (a) and (b) are respectively:

Option: 1

25 and 1


Option: 2

8 and 1


Option: 3

2 and 4


Option: 4

4 and 1


Answers (1)

Given:

a) n =5  and m =+1

    for  n = 4 , l = 0 to (n-1) , l = 0 to 3

    and m = -l to +l and each m value has 2 electrons.

     for  l = 0 , m = +1 not possible , so zero electrons.

     for l = 1 , m = +1 possible, so 2 electrons

     for l = 2 , m = +1 possible, so 2 electrons

     for l = 3 , m = +1 possible, so 2 electrons

     so, total 8 electrons with these quantum numbers.

b) n = 2 , l = 1 , m = -1 , ms = -1/2

All quantum numbers are given which is only single electrons.


The maximum number of electron(s) in an atom that can have quantum numbers as given in (a) and (b) are respectively 8 and 1.

Correct Option is 2.

Posted by

Ramraj Saini

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