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Given that the specific conductance of solution at 25^{\circ} \mathrm{C}  is   0.0314 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1} . The resistance of all containing solution at same temp found to be \mathrm{45 ohms}. Calculate the value of cell constant.

Option: 1

 1.628 
 


Option: 2

 1.413 


Option: 3

 2.37 


Option: 4

 2.66
 


Answers (1)

best_answer

\mathrm{ k=\frac{1}{R}\left(\frac{l}{a}\right) \\ }

\mathrm{ 0.0314=\frac{1}{45}\left(\frac{l}{a}\right) }

\mathrm{ \frac{l}{a}=0.0314 \times 45 \\ }

\mathrm{ \frac{l}{a}=1.413 }.

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Ritika Jonwal

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