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  • Gravitational field intensity due to a uniform circular ring of radius 'a' at the centre of the ring will be -Option: 1 <img alt="\frac{

Gravitational field intensity due to a uniform circular ring of radius 'a' at the centre of the ring will be -

Option: 1

\frac{Gm}{a^2}


Option: 2

\frac{Gm}{a}


Option: 3

zero


Option: 4

infinite


Answers (1)

As we have learnt,

 

Intensity due to uniform circular ring -

r\rightarrow Point on its Axis from ring

- wherein

At the centre of ring 

I=0

At a point on its Axis

I= \frac{GMr}{\left ( a^{2}+r^{2} \right )^{\frac{3}{2}}}

 

 

I= \frac{GMr}{\left ( a^{2}+r^{2} \right )^{\frac{3}{2}}} = 0 \; when \;r=0

Posted by

Kshitij

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