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A capacitor of 20\mu F  is charged upto 500V is connected in parallel with another capacitor of 10\mu F which is charged upto 200V. The common potential is

  • Option 1)

    500V

  • Option 2)

    400V

  • Option 3)

    300V

  • Option 4)

    200V

 

Answers (1)

best_answer

As we have learned 

Common Potential -

V=\frac{Total\: charge}{Total\: capacity}=\frac{Q_{1}+Q_{2}}{C_{1}+C_{2}}

V=\frac{C_{1}V_{1}+C_{2}V_{2}}{C_{1}+C_{2}}

-

 

 

 

    By using V= \frac{C_1V_1+C_2V_2}{C_1V_2} ;  C1 = 20 mF, V1 = 500 V, C2 = 10 mF and V2 = 200 V

V= \frac{20*500+10*200}{20+10}= 400V


Option 1)

500V

Option 2)

400V

Option 3)

300V

Option 4)

200V

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Aadil

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