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Selection of temperature to carry out a reduction process depends so as to make

  • Option 1)

    \DeltaG negative

  • Option 2)

    \DeltaG positive

  • Option 3)

    \DeltaH negative

  • Option 4)

    \DeltaH positive

 

Answers (1)

As we learnt

 

Thermodynamic principle of Metallurgy -

 

\bigtriangleup G=\bigtriangleup H-T\bigtriangleup S

also \bigtriangleup G^{\circ}= -RTlnK

- wherein

K is equilibrium constant.If \bigtriangleup G  for a reaction is negative reaction is fusible.

 

 For spontaneous process  \bigtriangleup G should be negative

 


Option 1)

\DeltaG negative

Option 2)

\DeltaG positive

Option 3)

\DeltaH negative

Option 4)

\DeltaH positive

Posted by

Vakul

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