Browse by Stream
QnA
Home
Search for Exam, Articles, Questions
QnA
get app
Go To Your Study Dashboard
  1. Home
  2. Help me answer: Standard heat formation of CH4(g), CO2(g) and water at 25°C are -17.9, -94.1 and -68.3 Kcal mol-1respectively. Calculate the heat change (in Kcal) in the following reaction at 25°C:CH4(g) + 2O2(g) = CO2(g)+ 2H2O(l)
# Engineering

Standard heat formation of CH4(g), CO2(g) and water at 25°C are -17.9, -94.1 and -68.3 Kcal mol-1 respectively. Calculate the heat change (in Kcal) in the following reaction at 25°C:

CH4(g) + 2O2(g) = CO2(g) + 2H2O(l)

  • Option 1)

    -144.5

  • Option 2)

    -180.3

  • Option 3)

    -248.6

  • Option 4)

    -212.8

 

Answers (1)
A Aadil.Khan

As learnt in

Enthalpy of combustion -

Amount of Enthalpy change when 1 mole of substance is completly burn in excess of Oxygen

- wherein

CO_{(g)}+\frac{1}{2}O_{2}(g)\rightarrow CO_{2(g)}+283\ KJ

\Delta H_{comb} \: of\: CO= 283\, KJ

 

 \Delta H = \Delta H_{p}- \Delta H_{R}

= -94.1 + 2 \times (-68.3)- (-17.9)

= -212.8

 


Option 1)

-144.5

Incorrect

Option 2)

-180.3

Incorrect

Option 3)

-248.6

Incorrect

Option 4)

-212.8

correct

Similar Questions

Preparation Products

Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 16999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
Start Now
 
Exams
Articles
Questions