Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me answer: The height at which the weight of a body becomes 1/16th, its weight on the surface of Earth (radius R), is:

The height at which the weight of a body becomes 1/16th, its weight on the surface of Earth (radius R), is:

  • Option 1)

    5R

  • Option 2)

    15R

  • Option 3)

    3R

  • Option 4)

    4R

 

Answers (1)

best_answer

Weight at surface of earth is =\frac{GmMe}{Re^{2}}

Weight at height h=\frac{GmMe}{(R+h)^{2}}

According to question 

\frac{1}{(R+h)^{2}}=\frac{1}{16}.\frac{1}{Re^{2}}

or R_{e}th=4Re\: or\: h=3Re


Option 1)

5R

This option is incorrect 

Option 2)

15R

This option is incorrect 

Option 3)

3R

This option is correct 

Option 4)

4R

This option is incorrect 

Posted by

Aadil

View full answer

Similar Questions

Latest Question