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  • Help me answer: - Two kg of a monoatomic gas is at a pressure of . The density of the gas is . What is the order of e - Kinetic theory of Gases - JEE Main

Two kg of a monoatomic gas is at a pressure of 4\times 10^{4}N/m^{2} . The density of the gas is 8\: K\! g/m^{3}. What is the order of energy of the gas due to its thermal motion?

 

  • Option 1)

     

    10^{5}J

  • Option 2)

    10^{3}J

  • Option 3)

    10^{6}J

  • Option 4)

    10^{4}J

Answers (3)

best_answer

 

Kinetic energy of a gas due to translation per mole -

E= \frac{3}{2}PV

= \frac{3}{2}RT
 

- wherein

R = Universal gas constant

T = temperature of gas

Thermal energy = N\frac{3}{2}KT

=\frac{N}{N_{A}}\frac{3}{2}RT

=\frac{3}{2}nRT

=\frac{3}{2}PV

=\frac{3}{2}P\left ( \frac{m}{8} \right )

=\frac{3}{2}\times 4\times 10^{4}\times \left ( \frac{2}{8} \right )=1.5\times 10^{3}

Ordrer is 103

 


Option 1)

 

10^{5}J

Option 2)

10^{3}J

Option 3)

10^{6}J

Option 4)

10^{4}J
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