Iodine reacts with concentrated HNO_{3} to yield Y along with other products . The oxidation state of iodine  in Y,  is :

  • Option 1)

    5

  • Option 2)

    3

  • Option 3)

    1

  • Option 4)

    7

Answers (1)
A admin

Oxidation state of oxygen family -

Oxygen shows -2,+2 and -1 

oxidation states other elements show +2,+4 and +6 oxidation states 

-

 

 

Rules for Oxidation Number -

The oxidation number of oxygen in most compounds is -2. There are two exceptions.
In peroxide (H2O2; Na2O2),  the oxidation number is -1.

- wherein

In superoxide e.g. KO2 its oxidation number is -1/2.

As we have learned in oxidation number the reaction is

I_{2}+10HNO_{3}\rightarrow 2HIO_{3}+10NO_{2}+4H_{2}O

y\, \, is\, \, HIO_{3}and how +5 oxidation state of iodine

as 1+x+\left ( 3x\left ( -2 \right ) \right )= 0

x= 6-1= 5

 


Option 1)

5

Option 2)

3

Option 3)

1

Option 4)

7

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