Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me please, - Iodine reacts with concentrated to yield Y along with other products . The oxidation state of iodin - Redox Reaction and Electrochemistry - JEE Main

Iodine reacts with concentrated HNO_{3} to yield Y along with other products . The oxidation state of iodine  in Y,  is :

  • Option 1)

    5

  • Option 2)

    3

  • Option 3)

    1

  • Option 4)

    7

Answers (1)

best_answer

Oxidation state of oxygen family -

Oxygen shows -2,+2 and -1 

oxidation states other elements show +2,+4 and +6 oxidation states 

-

 

 

Rules for Oxidation Number -

The oxidation number of oxygen in most compounds is -2. There are two exceptions.
In peroxide (H2O2; Na2O2),  the oxidation number is -1.

- wherein

In superoxide e.g. KO2 its oxidation number is -1/2.

As we have learned in oxidation number the reaction is

I_{2}+10HNO_{3}\rightarrow 2HIO_{3}+10NO_{2}+4H_{2}O

y\, \, is\, \, HIO_{3}and how +5 oxidation state of iodine

as 1+x+\left ( 3x\left ( -2 \right ) \right )= 0

x= 6-1= 5

 


Option 1)

5

Option 2)

3

Option 3)

1

Option 4)

7

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE Mains session 2 results at jeemain.nta.ac.in soon; rank predictor
anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores
anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question