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- Help me solve this - Co-ordination Compounds - JEE Main-2
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Nickel ( Z = 28 ) combines with a uninegative monodentate ligand to form a paramagnetic complex
The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively
- Option 1)
one, tetrahedral
- Option 2)
two, tetrahedral
- Option 3)
one, square planar
- Option 4)
two, square planar.
Answers (1)
As we learned
Hybridisation -
sp3d2 - square bipyramidal or octahedral
d2sp3 - octahedral
sp3 - tetradedral
dsp2 - square planar
- wherein
sp3d2 - outer complex
d2sp3 - inner complex
sp3 -
dsp2 -
Electronic configuration of Ni2+ for this complex :
Sp3 hybridisation suggests tetrahedral geometry,
no. of unpaired electrons = 2
Option 1)
one, tetrahedral
Option 2)
two, tetrahedral
Option 3)
one, square planar
Option 4)
two, square planar.
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