Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me solve this - Sets, Relations and Functions - JEE Main-6

If\: \: n(A\cup B\cup C)= 100,n\left ( A \right )= 30,n\left ( B \right )=90,n\left ( C \right )= 40,n\left ( A\cap B \right )= 10,n\left ( B\cap C \right )= 20,n\left ( C\cap A \right )= 30.\: \: Then\: \: n\left ( A\cap B\cap C \right )=

  • Option 1)

    0

  • Option 2)

    20

  • Option 3)

    30

  • Option 4)

    40

 

Answers (1)

best_answer

As we learnt

 

Number of Elements in Union A , B & C -

 

n (A ∪ B ∪ C) = n (A) + n (B) + n (C) – n (A ∩ B) – n (A ∩ C) – n (B ∩ C) + n (A ∩ B ∩ C)

- wherein

Given A, B and C be any finite sets. then Number of Elements in union A , B & C is given by this formula.

 

  

n (A ∪ B ∪ C) = n (A) + n (B) + n (C) – n (A ∩ B) – n (A ∩ C) – n (B ∩ C) + n (A ∩ B ∩ C)

100=30+90+40-10-20-30+ n (A ∩ B ∩ C)

\thereforen (A ∩ B ∩ C)=0


Option 1)

0

Option 2)

20

Option 3)

30

Option 4)

40

Posted by

Himanshu

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 session 2 final answer key soon at jeemain.nta.ac.in; result on April 25
anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today
anam-khan

BTech admission 2024 without JEE; top government engineering colleges, upcoming entrance exams

Latest Question