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The output of the given logic circuit is :
Option 1)
$A\bar{B} + \bar{A}B$
Option 2)
$A\bar{B}$
Option 3)
$AB + \bar{AB}$
Option 4)
$\bar{A}B$

Answers (1)

best_answer

D'morgan's Theorem -

1) $\overline{A+B }= \bar{A}\cdot \bar{B}$

2) $\overline{A\cdot B }= \bar{A}+ \bar{B}$

3) $\overline{\bar A+ \bar B }= {A}\cdot {B}$

4) $\overline{\bar A\cdot \bar B }= {A}+{B}$

- wherein

A and B are input.

$Y=\overline{\left ( \bar{A}+AB \right )\cdot \left ( \overline{AB}+B\right )}$

or $Y =\overline{A\cdot \overline{AB}}+\overline{\overline{AB}+B}$

$=A.\overline{AB}+\left ( AB.\bar{B} \right )$

$=A\left ( \bar{A}+\bar{B} \right )+AB\cdot \bar{B}$

$Y=A\bar{B}+O$

$Y=A\bar{B}$

Option 1)

$A\bar{B} + \bar{A}B$

Option 2)
$A\bar{B}$
Option 3)

$AB + \bar{AB}$

Option 4)

$\bar{A}B$

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