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  • Help me understand! Distance travelled by a free falling body during 3rdsecond of its motion is ( g = 10m/s2)

Distance travelled by a free falling body during 3rd second of its motion is ( g = 10m/s2)

  • Option 1)

    15 m

  • Option 2)

    25 m

  • Option 3)

    35 m

  • Option 4)

    30 m

 

Answers (1)

best_answer

As we have learnt,

 

Displacement in nth second for freely falling body -

h_{n}= \frac{g}{2}\left ( 2n-1 \right )
 

- wherein

\\*u=0\\* a=g\left ( Acceleration \: due\: to \: gravity \right )

n= nth second

 

 Distance travelled during nth second is 

s_n = \frac{1}{2} g (2n-1)

For n = 3

s_3 = \frac{1}{2} g (2\times 3-1) = 25 m

 

 

Displacement in nth second for freely falling body -

h_{n}= \frac{g}{2}\left ( 2n-1 \right )
 

- wherein

\\*u=0\\* a=g\left ( Acceleration \: due\: to \: gravity \right )

n= nth second

 

 


Option 1)

15 m

Option 2)

25 m

Option 3)

35 m

Option 4)

30 m

Posted by

Plabita

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