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 A parallel plate capacitor is made of two   circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them.  When the electric field in the dielectric is 3\times104 V/m, the charge density of the positive plate will be close to :        

 

  • Option 1)

    6\times 10^{-7} C/m^{2}

  • Option 2)

    3\times 10^{-7} C/m^{2}

  • Option 3)

    3\times 10^{4} C/m^{2}

  • Option 4)

    6\times 10^{4} C/m^{2}

 

Answers (2)

best_answer

As we discussed in the concept

Infinite Plane Parallel sheets of charge -

If  

 \sigma _{A}=\sigma _{B}=\sigma \rightarrow \left | E_{p} \right |=\left | E_{R} \right |=\frac{\sigma }{\epsilon _{0}}

and  EQ = 0

-

 

 E=\frac{\sigma }{K \epsilon_{0}}

 

\therefore Charge density \sigma =K \epsilon _{0}E

                                   = 2.2\times 8.85\times 10^{-12}\times 3\times 10^{4}

\sigma = 6\times 10^{-7} c/m^{2}


Option 1)

6\times 10^{-7} C/m^{2}

Option 2)

3\times 10^{-7} C/m^{2}

Option 3)

3\times 10^{4} C/m^{2}

Option 4)

6\times 10^{4} C/m^{2}

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