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Find the median of the following frequency distribution


 

x

8

5

6

10

9

4

7

f

6

4

5

8

9

6

4

  • Option 1)

    6

  • Option 2)

    8

  • Option 3)

    10

  • Option 4)

    12

 

Answers (1)

best_answer

As we learned

 

MEDIAN -

For Grouped discrete frequency distribution :

In case of continuous frequency distribution the class corresponding the cumulative frequency Just greater than \frac{N}{2}  is called the median class and the value of the median

= l+\frac{h}{f}\left ( \frac{N}{2}-c \right )

l = the lower limit of the median class.

f = the frequency of the median class.

h = the magnitude of the median class. 

c = the cumulative frequency of the class preceding the median class

 

 

 

- wherein

where 

N= \sum_{i=1}^{n}f_{i}

 

We note that the values of x are not given in ascending order. Hence, we first arrange the values of x in ascending order and then form the cumulative frequency table. We have the following table

x

f

Cumulative frequency

4

5

6

7

8

9

10

6

4

5

4

6

9

8

6

10

15

19

25

34

42

 The total frequency n = 42 is even. We have

 \frac{n}{2}=\frac{42}{2}=21 and\frac{n}{2}+1=22.

The values of the 21st and 22nd items are 8, 8 since the values of the items from 20 to 25 are 8 each. Therefore median

=\frac{1}{2}(8+8)=8.

.


Option 1)

6

Option 2)

8

Option 3)

10

Option 4)

12

Posted by

Himanshu

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