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  • How to solve this problem- - A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive At a part - Electromagnetic Waves - JEE Main

A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point in space and time, \vec{E}=6.3\, \hat{j}\, \, V/m. The corresponding magnetic field \vec{B}, at that point will be :

  • Option 1)

    18.9\times 10^{-8}\, \, \hat{k}T\; \;

     

  • Option 2)

    2.1\times 10^{-8}\,\, \hat{k}T\; \;

  • Option 3)

    6.3\times 10^{-8}\,\, \hat{k}T\; \;

  • Option 4)

    18.9\times 10^{8}\,\, \hat{k}T\; \;

Answers (1)

best_answer

 

Relation between Eo and Bo -

E_{o}=c.B_{o}

- wherein

E_{o}= Electric field amplitude

B_{o} = Magnetic field amplitude

C= Speed of light in vacuum

 

\left | B \right | = \frac{\left | E \right |}{C} = \frac{6.3}{3 \times 10^{8}} = 2.1 \times 10^{-8} T

Direction \hat{E} \times \hat{B} = \hat{C}

\hat{j} \times \hat{B} = \hat{i}

\therefore \hat{B} = \hat{K}

\vec{B} = 2.1 \times 10^{-8} \hat{K}

 


Option 1)

18.9\times 10^{-8}\, \, \hat{k}T\; \;

 

Option 2)

2.1\times 10^{-8}\,\, \hat{k}T\; \;

Option 3)

6.3\times 10^{-8}\,\, \hat{k}T\; \;

Option 4)

18.9\times 10^{8}\,\, \hat{k}T\; \;

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