Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • How to solve this problem- Two integers are selected at random from the set {1,2,...........11}. Given that the sum of selected numbers is even, the conditional probability that both the numbers are even is:

 

Two integers are selected at random from the set {1,2,...........11}. Given that the sum of selected numbers is even, the conditional probability that both the numbers are even is:

  • Option 1)

     

    \frac{3}{5}

  • Option 2)

     

    \frac{1}{2}

  • Option 3)

     

    \frac{7}{10}

  • Option 4)

     

    \frac{2}{5}

Answers (1)

best_answer

 

Conditional Probability -

 

P\left ( \frac{A}{B} \right )= \frac{P\left ( A\cap B \right )}{P\left ( B \right )}

and

P\left ( \frac{B}{A} \right )= \frac{P\left ( A\cap B \right )}{P\left ( A \right )}

 

- wherein

where P\left ( \frac{A}{B} \right ) probability of A when B already happened.

 

from 1 to 11 , 6 = odd 5= even 

P\left ( \frac{number\; are\; even}{sum\; are\; even} \right )=\frac{^{5}\textrm{C}_{2}}{^{5}\textrm{C}_{2}+^{6}\textrm{C}_{2}}=\frac{10}{10+15}=\frac{2}{5}


Option 1)

 

\frac{3}{5}

Option 2)

 

\frac{1}{2}

Option 3)

 

\frac{7}{10}

Option 4)

 

\frac{2}{5}
Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: IIT Roorkee’s ECE emerges as top choice after CSE; closing rank rises
anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus

Latest Question