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  • I have a doubt, kindly clarify. A box contains 15 green and 10 yellow balls. If 10 balls are randomly drawn, one-by-one, with replacement, then the variance of the number of green balls drawn is :

A box contains 15 green and 10 yellow balls.  If 10 balls are randomly drawn, one-by-one, with replacement, then the variance of the number of green balls drawn is :

 

  • Option 1)

    6

  • Option 2)

    4

  • Option 3)

    \frac{6}{25}

  • Option 4)

    \frac{12}{5}

 

Answers (1)

best_answer

As we have learned

Binomial Distribution(Statistical) -

Mean = np

Variance = npq

Standard \: deviation =\sqrt{npq}

-

 

 Variance  = npq

Where n = 10 

p = probability of drwing green balls  

= 15/25 = 3/5 

q = 1-p = 2/5 

Variance = 10\times \frac{3}{5}\times \frac{2}{5} = 12/5

 


Option 1)

6

Option 2)

4

Option 3)

\frac{6}{25}

Option 4)

\frac{12}{5}

Posted by

gaurav

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