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A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by

  • Option 1)

    2\pi R^2E

  • Option 2)

    \pi R^2/E

  • Option 3)

    (\pi R^2-\pi R)/E

  • Option 4)

    zero

 

Answers (1)

best_answer

As we have learned

Electric field E through any area A -

\phi = \vec{E}\cdot \vec{A}=EA\cos \Theta

S.I\; unit\; -\left ( volt \right )m\; or\; \frac{N-m^{2}}{c}

 

 

- wherein

 

 

         Flux through surface A_{\phi A}= E\times \pi R^2  and {\phi B}= E\times \pi R^2

Flux through curved surfaceC=\int Eds=\int Eds \cos 90 \degree = 0 

 Total flux through cylinder =\phi _A+\phi _B+\phi _C=0 

 


Option 1)

2\pi R^2E

Option 2)

\pi R^2/E

Option 3)

(\pi R^2-\pi R)/E

Option 4)

zero

Posted by

prateek

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