Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I have a doubt, kindly clarify. A metal is known to form MF2. When 10 ampere electricity is passes through a motten salt for 330 s, 195 g metal is deposited. Find out the atomic weight of the metal and what quantity of charge will be required to depo

A metal is known to form MF2. When 10 ampere electricity is passes through a motten salt for 330 s, 195 g metal is deposited. Find out the atomic weight of the metal and what quantity of charge will be required to deposit the same mass of Cu from CuSO4?

  • Option 1)

    57, 5917.45 C

  • Option 2)

    55, 5997.67 C

  • Option 3)

    62, 5721.60 C

  • Option 4)

    61, 5791.98 C

 

Answers (1)

As we have learnt,

 

Second law of electrolysis -

The masses of different substances, liberated or dissolved by the electricity are proportional to their equivalent masses.

-

 

 Eq of metal  = \frac{i\cdot t}{96500}

 

\Rightarrow \frac{1.95}{E} = \frac{10\times 330}{96500} \Rightarrow E_{metal} = 57.0

at. wt\;of\;metal = 57.0\times 2 = 114

also, if WCu = 1.95 g then,

Eq. of Cu = \frac{i\cdot t}{96500} \\*\Rightarrow \frac{1.95}{63\cdot\frac{63}{2}} = \frac{i\cdot t}{96500} \\*\Rightarrow i\cdot t = Q = 5917.45 C

 


Option 1)

57, 5917.45 C

Option 2)

55, 5997.67 C

Option 3)

62, 5721.60 C

Option 4)

61, 5791.98 C

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 session 2 result date announced; Steps to check NTA session 2 scores
anam-khan

JEE Main 2024 session 2 final answer key soon at jeemain.nta.ac.in; result on April 25
anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today

Latest Question