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  • I have a doubt, kindly clarify. - Electrostatics - JEE Main-6

The dimension of \frac{1}{2}\epsilon_0 E^2(\epsilon_0 : permittivity of free space; E : electric field) is

  • Option 1)

    MLT-1

  • Option 2)

    ML2T-2

  • Option 3)

    ML-1T-2

  • Option 4)

    ML2T-1

 

Answers (1)

best_answer

As we have learnt,

 

Energy density -

The energy stored for unit volume.

 

 

 

- wherein

U_{v}=\frac{U}{V}

U-Potential\, Energy

V-Volume.

 

 

Energy density = \frac{Energy}{Volume}

so it’s dimensions are \frac{ML^2T^{-2}}{L^3} = [ML^{-1}T^{-2}]

 


Option 1)

MLT-1

Option 2)

ML2T-2

Option 3)

ML-1T-2

Option 4)

ML2T-1

Posted by

Aadil

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