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The correct order of spin-only magnetic
moments among the following is :
(Atomic number : Mn=25, Co=27,
Ni=28, Zn=30)

  • Option 1)

    [ZnCl4 ] 2− > [NiCl 4 ] 2− > [CoCl4 ] 2− > [MnCl 4 ] 2−

  • Option 2)

    [CoCl4 ] 2− > [MnCl 4 ] 2− > [NiCl4 ] 2− > [ZnCl 4 ] 2−

  • Option 3)

     [NiCl 4 ] 2− > [CoCl4 ] 2− > [MnCl 4 ] 2−  > [ZnCl4 ] 2−

  • Option 4)

     [MnCl 4 ] 2− > [CoCl4 ] 2− > [NiCl 4 ] 2−  > [ZnCl4 ] 2−

 

Answers (2)

best_answer

As we learnt in

Magnetic Moments (spin only) -

\sqrt{n\left ( n+2 \right )} where n= number of unpaired electron.

- wherein

Number of unpaired e^{-} s and corresponding magnetic moments

1\rightarrow 1.7\\2\rightarrow 2.8\\3\rightarrow 3.9\\4\rightarrow 4.9\\5\rightarrow 5.9

 

 

Spin only magnetic moment \propto number of unpaired electrons

Compound Number of unpaired electrons

[MnCl4]2-

5

[CoCl4]2-

3

[NiCl4]2-

2

[ZnCl4]2-

Zero

 


Option 1)

[ZnCl4 ] 2− > [NiCl 4 ] 2− > [CoCl4 ] 2− > [MnCl 4 ] 2−

Option 2)

[CoCl4 ] 2− > [MnCl 4 ] 2− > [NiCl4 ] 2− > [ZnCl 4 ] 2−

Option 3)

 [NiCl 4 ] 2− > [CoCl4 ] 2− > [MnCl 4 ] 2−  > [ZnCl4 ] 2−

Option 4)

 [MnCl 4 ] 2− > [CoCl4 ] 2− > [NiCl 4 ] 2−  > [ZnCl4 ] 2−

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