Two elements X and Y have atomic weights of 14 and 16.They form a series of compounds A,B,C,D and E in which the same amount of element X,Y is present in the ratio 1 : 2 : 3 : 4 : 5. If the compound A has 28 parts by weight of X and 16 parts by weight of Y,then the compound of C will have 28 parts weight of X and
A) 32 parts by weight of Y
B) 48 parts by weight of Y
C) 64 parts by weight of Y
D) 80 parts by weight of Y
Option(B) is correct.
Amount of 'X' in each compound(A,B,C,D,E) is same but amount of "Y" varies in ratio of 1:2:3:4:5 in A:B:C:D:E respectively.
So, if amount of 'X' in comp.'A' is 28 parts and of 'Y' is 16 parts, then in compund 'C' amount of 'X' will remains same but amount of 'Y' increases 3 times the amount of 'Y' in comp. A.
Hence the amount of 'Y' in compound C is 48 parts by weight.
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