Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I need help with Calculate the mass of Hg2Cl2which can be prepared byt the reduction of mercury (II) ions in presence of chloride ions by the passage of % amepre current for 3 hrs.

Calculate the mass of Hg2Cl2 which can be prepared byt the reduction of mercury (II) ions in presence of chloride ions by the passage of % amepre current for 3 hrs.

  • Option 1)

    124.68 g

  • Option 2)

    143.34 g

  • Option 3)

    136.46 g

  • Option 4)

    132.00 g

 

Answers (1)

As we have learnt,

 

Faraday's first law of electrolysis -

The mass of any substance deposited or dissolved at any electrode during electrolysis is directly propotional to the quantity of electricity passed through the solution.

- wherein

W\alpha\ Q

W = Z I t

Z = mass of electrolyte get deposited

Z = electro chemical equivalent

 

 2Hg^{2+} + 2Cl^- + 2e^- = Hg_2Cl_2

                                      2F            1 mol    

\\*2F\rightarrow1 mol \\*0.56\rightarrow 0.5\times 0.55 9 mol

\therfore mass = 0.5\times 0.56\times (2\times 200 + 71) \\*mass = 132 g


Option 1)

124.68 g

Option 2)

143.34 g

Option 3)

136.46 g

Option 4)

132.00 g

Posted by

subam

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: IIT Roorkee’s ECE emerges as top choice after CSE; closing rank rises
anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus

Latest Question