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 A pipe open at both ends has a fundamental frequency f in air.  The pipe is dipped vertically in water so that half of it is in water.  The fundamental frequency of the air column is now :

  • Option 1)

    \frac{f}{2}

  • Option 2)

    \frac{3f}{4}

  • Option 3)

    2f

  • Option 4)

    f

 

Answers (1)

best_answer

As we learned

 

The frequency in closed organ pipe -

\nu = \left ( 2n+1 \right )\frac{V}{4l}

n= 0,1,2,3...............
 

- wherein

V= velocity of sound wave

l= length of pipe

n= number of overtones

 

The frequency in open organ pipe -

\nu = n\cdot \frac{V}{2l}

n= 1,2,3.......

- wherein

V= velocity of sound wave

l= length of pipe

n= number of overtones

 

 for open pipe:

f_{n}=n\left ( \frac{V}{2e} \right )

f_{1}=n\left ( \frac{V}{2e} \right )

closed pipe, f_{1}=\frac{V}{4{e}'}

=\frac{V}{4\cdot (\frac{e}{2})}=\frac{V}{2e}=f 


Option 1)

\frac{f}{2}

Option 2)

\frac{3f}{4}

Option 3)

2f

Option 4)

f

Posted by

Plabita

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