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  • I need help with - Sets, Relations and Functions - JEE Main-11

What is the inverse of y = \sqrt{x + 3} - 2

  • Option 1)

    x^2 + x + 4

  • Option 2)

    x^2 + 4x + 1

  • Option 3)

    x^2 + 4x + 4

  • Option 4)

    x^2 + x + 1

 

Answers (1)

best_answer

As we have learnt,

 

Property of Inverse -

The inverse of a bijection is also a bijection.

-

 

 y = \sqrt{x + 3} - 2 \Rightarrow y + 2 = \sqrt{x + 3}

Squaring both sides

y^2 + 4y + 4 = x + 3

x =y^2 + 4y + 1

Thus inverse is y =x^2 + 4x + 1

 


Option 1)

x^2 + x + 4

Option 2)

x^2 + 4x + 1

Option 3)

x^2 + 4x + 4

Option 4)

x^2 + x + 1

Posted by

Himanshu

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