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  • I need help with Steel ruptures when a shear of 3.5x108 N m-2 is applied. The force needed to punch a 1 cm diameter hole in a steel sheet 0.3 cm thick is nearly :

  Steel ruptures when a shear  of 3.5x108 N m-2 is applied. The force needed to punch a 1 cm diameter hole in a steel sheet 0.3 cm thick is nearly :

  • Option 1)

     1.4 x 104 N

  • Option 2)

     2.7 x 104 N

  • Option 3)

     3.3 x 104 N

  • Option 4)

     1.1 x 104 N

 

Answers (1)

best_answer

As we have learned

Stress -

Stress =\frac{force}{Area}=\frac{F}{A}
 

- wherein

F= applied \: force

A= area \:

 

 F = stress * Area 

= \sigma \cdot 2 \pi rl

\sigma =3.5 \times 10 ^8 N/m^2\\r = 0.5 cm \\l = 0.3 cm \\ F = 3.3 \times 10 ^4 N

 

 

 

 

 

 


Option 1)

 1.4 x 104 N

Option 2)

 2.7 x 104 N

Option 3)

 3.3 x 104 N

Option 4)

 1.1 x 104 N

Posted by

SudhirSol

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