The resistance of the filament of an electric bulb changes with temperature. If an electric bulb rated 220 volt and 100 watt is connected to (220×.8) volt sources, then the actual power would be
100×0.8 watt
100× (0.8)2 watt
Between 100×0.8 watt and 100 watt
Between 100× (0.8)2 watt and 100×0.8 watt
As we learnt in
Power dissipiated in external resistance -
-
Applied Voltage=
maximum power =
Option 1)
100×0.8 watt
This solution is incorrect
Option 2)
100× (0.8)2 watt
This solution is incorrect
Option 3)
Between 100×0.8 watt and 100 watt
This solution is incorrect
Option 4)
Between 100× (0.8)2 watt and 100×0.8 watt
This solution is correct