The sum of integers from 1 to 100 that are divisible by 2 or 5 is
3000
3050
3600
3250
As we have learned
Number of Elements in Union A & B -
n (A ∪ B) = n (A) + n (B) – n (A ∩ B)
- wherein
Given A and B be any finite sets. then Number of Elements in union A & B is given by this formula.
S = 2+4+5+6
= (sum of integers divisible by 2 ) + (sum of integers divisible by 5) - (sum of integers divisible by 10 ())
= (2+4+6+8..........100) + (5+10+15..........100) - (10+20+.............10)
Option 1)
3000
Option 2)
3050
Option 3)
3600
Option 4)
3250
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