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  • Identify the reaction order for rate constant, <img alt="\mathrm k=7.06 \times 10^{-3} \mathrm{mol} \mathrm{\: L}^{-1} \mathrm{s}^{-1}" src="http://entrancecorner.oncodecogs.com/gif.latex

Identify the reaction order for rate constant, \mathrm k=7.06 \times 10^{-3} \mathrm{mol} \mathrm{\: L}^{-1} \mathrm{s}^{-1}.

Option: 1

First


Option: 2

Second


Option: 3

Zero


Option: 4

Third


Answers (1)

best_answer

As we have learnt,

The differential rate expression for nth order reaction is as follows:
                       -\frac{\mathrm{dx}}{\mathrm{dt}}=\mathrm{k}(\mathrm{a}-\mathrm{x})^{\mathrm{n}}
\text { or } \quad \mathrm{k}=\frac{\mathrm{d} \mathrm{x}}{(\mathrm{a}-\mathrm{x})^{\mathrm{n}} \mathrm{dt}}=\frac{(\text { concentration })}{(\text { concentration })^{\mathrm{n}} \text { time }}=(\text { conc. })^{1-\mathrm{n}} \text { time }^{-1}
Upon comparing the units of rate constant, we have 

n = 0

Hence, given reaction is zero order reaction.

Therefore, option(3) is correct

Posted by

Pankaj

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