If a 5 Kg mass is suspended by a spring balance in a lift which is accelerated downward at 10 m/s 2 .The reading of the balance is
more than 5Kg weight
is less than 5Kg weight and greater than zero
is equal to 5 Kg weight
zero
Apparent weight of body in a lift when Lift is moving down with a = g
As
Apparent weight = 0 (weightlessness)
Draw FBD of block
mg- T = mg
T= 0
so reading of balance is zero