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If half-life of a substance is 3.8 days and its quantity is 10.38 g. Then, substance quantity remaining left after
19 days will be:

Option: 1

0.151 g


Option: 2

0.32 g


Option: 3

1.51 g


Option: 4

0.16 g


Answers (1)

best_answer

Number of half-lives, \mathrm{n}=\frac{19}{3.8}=5

\text { Now, } \frac{\mathrm{N}}{\mathrm{N}_0}=\left(\frac{1}{2}\right)^{\mathrm{n}}

\Rightarrow \frac{\mathrm{N}}{10.38}=\left(\frac{1}{2}\right)^5 \Rightarrow \mathrm{N}=10.38 \times\left(\frac{1}{2}\right)^5=0.32 \mathrm{~g}

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