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If Q amount of heat supplied to a gas and work done by the gas is W , then specific heat will be negative if 

Option: 1

Q < W 


Option: 2

Q > W 


Option: 3

Q = W 


Option: 4

can never be negative 


Answers (1)

best_answer

As we have learned

If Delta theta negative -

C=\frac{Q}{m(-\Delta \theta)}

- wherein

The fall in temperature of the gas due to expansion would be greater than the rise in temperature of the gas due to heat supplied.

 

 Q < W 

\Delta U is negative 

\Delta T is negative 

 

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Rishi

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